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-4x^2-12x+112=0
a = -4; b = -12; c = +112;
Δ = b2-4ac
Δ = -122-4·(-4)·112
Δ = 1936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1936}=44$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-44}{2*-4}=\frac{-32}{-8} =+4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+44}{2*-4}=\frac{56}{-8} =-7 $
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